9x+49=X^2

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Solution for 9x+49=X^2 equation:



9x+49=x^2
We move all terms to the left:
9x+49-(x^2)=0
determiningTheFunctionDomain -x^2+9x+49=0
We add all the numbers together, and all the variables
-1x^2+9x+49=0
a = -1; b = 9; c = +49;
Δ = b2-4ac
Δ = 92-4·(-1)·49
Δ = 277
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{277}}{2*-1}=\frac{-9-\sqrt{277}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{277}}{2*-1}=\frac{-9+\sqrt{277}}{-2} $

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